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This theory may be applied to turbines and pump blade theory as well as to pipe bends. SELF ASSESSMENT EXERCISE No.1 1. A pipe bends through an angle of 90o in the vertical plane. At the inlet it has a cross sectional area of 0.003 m2 and a gauge pressure of 500 kPa. At exit it has an area of 0.001 m2 and a gauge pressure of 200 kPa.

Learn MoreExample A water-mounted fire pump (an old exam problem.) Given: A pump is anchored to the ground as shown, with V j =35.0 m/s and d j =3.00 cm. Assume the jet has a fully developed turbulent pipe flow profile at its exit. picture wat_pump.gif Find: Horizontal force required to hold platform in place. Solution

Learn MoreQ = flow rate through the pipe (m 3 /sec) A = pipe cross s ectional area (CSA) (m 2 ) If Q is 2500 m 3 /hr and the flow is pumped through a 0.8 m diameter pipe then: 0 . 5 4 0 . 8 4 2 f2 = = · = = p p D A m 2 Hence, using equation (4), we get: 1 . 39 0 . 5 1 3600 25000

Learn Morehard-to-clean areas, so a steady flow can funnel down the angled hopper sides. Cleanup is a breeze. (N/A – TK 7, TK 10, TK 20, TK 15HP) saFer Depend on electric cycling for reversibility at any point in the stroke and to relieve pressure from the concrete for safer pipeline cleanout in case of blockages. Wider

Learn More8.34 Steady-state creep rate data are given below for nickel at 1000°C (1273 K): ˙ ! s (s –1) σ [MPa (psi)] 10–4 15 (2175) 10–6 4.5 (650) If it is known that the activation energy for creep is 272,000 J/mol, compute the steady-state creep rate at a temperature of 850°C (1123 K) and a stress level of 25 MPa (3625 psi). Solution

Learn MoreAssumptions 1 This is a steady-flow process since there is no change with time. 2 Potential energy changes are negligible. 3 The device is adiabatic and thus heat transfer is negligible. Properties From the steam tables (Tables A-4 through 6) 1 3240.9kJ/kg 0.02975m /kg 450 C 10MPa 1 3 1 1 = = ⎪⎭ ⎪ ⎬ ⎫ = = h v T P o STEAM m = 12 kg/s

Learn MoreSteady flow into and out of a tank. Obtained from the following intuitive arguments: Volume flow rate: 𝑄= 𝑉𝐴. Mass flow rate: 𝑚̇= 𝜌𝑄= 𝜌𝑉𝐴. Conservation of mass requires 𝜌 1 𝑉 1 𝐴 1 = 𝜌 2 𝑉 2 𝐴 2. For incompressible flow 𝜌 1 = 𝜌 2, we have 𝑉 1 𝐴 1 = 𝑉 2 𝐴 2. or 𝑄 1 = 𝑄 2

Learn MoreTemperatures remain steady for _____ periods of time on hydronic systems than in forced air systems. What type of motor driven pump controls water flow through the system piping. a signal for heat that causes the _____ to open a solenoid or plunger inside the valve body allowing heated water to flow through the zone. Actuator Pg797 19th.

Learn MoreAlso, the velocity and the flow rate will decrease as the water level in the tank decreases. Example: The water in a 10-m-diameter, 2-m-high aboveground swimming pool is to be emptied by unplugging a 3-cmdiameter, 25-m-long horizontal pipe attached to the bottom of the pool. Determine the maximum discharge rate of water through the pipe.

Learn MoreSOLUTION OF VISCOUS-FLOW PROBLEMS 6.1 Introduction the °ow is assumed to be steady, laminar and Newtonian, with constant density and viscosity. Although these as-sumptions are necessary in order to obtain solutions, they are nevertheless realistic Fig. E6.1.1 Geometry for °ow through a …

Learn MoreAssumptions 1 This is a steady-flow process since there is no change with time. 2 Potential energy changes are negligible. 3 The device is adiabatic and thus heat transfer is negligible. Properties From the steam tables (Tables A-4 through 6) 1 3240.9kJ/kg 0.02975m /kg 450 C 10MPa 1 3 1 1 = = ⎪⎭ ⎪ ⎬ ⎫ = = h v T P o STEAM m = 12 kg/s

Learn MoreFind the head loss due to the flow of 1,500gpm of oil (ν= ×1.15 10 /−42 ft s) through 1,600 feet of 8" diameter cast iron pipe. If the density of the oil . ρ=1.75 / slug ft. 3, what is the power to be supplied by a pump to the fluid? Find the BHP of the pump if its efficiency is 0.85. Solution . We have the following information. ρ=1.75

Learn More3. A liquid of dynam ic viscosity 5 x 10 -3 Ns/m 2 flows through a ca pillary of diam eter 3.0 mm under a pressure gradient of 1800 N/ m 3. Evaluate the volum etric flow ra te, the m ean velocity, the cen tre line velocity and the radial position at which th e velocity is e qual to the m ean velocity. u 0.10125 m/s d 32 µ u 1800 L û P 2 m m

Learn MoreSimple stage pump: Only one impeller is mounted on the shaft. Multistage pump: Several impellers are mounted on the same shaft. DThe flowrate is the same through all stages. DEach stage develops an additional pressure rise. DFor a very large discharge pressure.

Learn MoreMay 22, 2019 · Water at 20°C is pumped through a smooth 12-cm-diameter pipe 10 km long, at a flow rate of 75 m 3 /h. The inlet is fed by a pump at an absolute pressure of 2.4 MPa. The exit is at standard atmospheric pressure (101 kPa) and is 200 m higher. Calculate the frictional head loss H f, and compare it to the velocity head of the flow v 2 /(2g). Solution

Learn Morerate and mean flow velocity as avg A V V n dAc mV c ( ) . The value of is unity for uniform flow, such as a jet flow, nearly unity for fully developed turbulent pipe flow (between 1.01 and 1.04), but about 1.3 for fully developed laminar pipe flow. So it is significant and should be considered in laminar flow; it is often ignored in turbulent flow.

Learn More4. Consider the tank and disk flow system shown in the figure below. Flow discharges to air through the thin gap between the two disks. Water in the tank is pressurized. Gauge fluid is also water. All dimensions are shown in the figure. Neglect water level change in the tank and the viscous effect. Find: (a) (3points) Air pressure in region 1

Learn MoreA pump steadily draws water through a pipe from a reservoir at a volumetric flow rate of 20 gal/min. At the pipe inlet, the pressure is 14.7 lbf/in.2, the temperature is 64 F, and the velocity is 1

Learn More3. With the flow regulating valve of the bench closed, switch on the bench pump and allow water to be pumped into the apparatus by controlling the opening of the flow regulating valve until water just begins to flow into the equipment and just overflows through the air vent above the rotameter.

Learn Moreand pumps or sucks air through the orifice. Because of the restriction, pressure is needed to make the air flow through the orifice and this pressure will produce a force opposing the motion. Often the piston is replaced with a simple diaphragm. OIL-The oil is contained in the cylinder and motion of the piston pushes the oil through

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